Now divide each by 11 and see if integer:
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- To allow $ B $ to divide a number $ D \in [100,199] \cap 9\mathbb{Z} $, it suffices that $ B $ divides at least one such $ D $.
- So we seek the smallest multiple of 11 that divides at least one multiple of 9 in [100,199].
- List multiples of 9 in range: 108, 117, 126, 135, 144, 153, 162, 171, 180, 189, 198
- ÷ 11 = 9.818 â not
- ÷ 11 â 10.636 â no
- So only 198 is divisible by 11.
