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/ For $ m = 0 $, $ L = 14 $ (two-digit)
For $ m = 0 $, $ L = 14 $ (two-digit)
February 22, 2026
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So $ 7^{-1} \equiv 2 \pmod{13} $
k \equiv 2 \pmod{13} \Rightarrow k = 13m + 2
Then $ L = 7k = 7(13m + 2) = 91m + 14 $
Check: Is 14 $ \equiv 1 \pmod{13} $?
$ 14 \div 13 = 1 $ remainder 1 â yes.
And 14 is a multiple of 7 â valid.
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